1/6t^2-4/3t+2=0

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Solution for 1/6t^2-4/3t+2=0 equation: 


t in (-oo:+oo)

(1/6)*t^2-((4/3)*t)+2 = 0

(1/6)*t^2+(-4/3)*t+2 = 0

1/6*t^2-4/3*t+2 = 0

DELTA = (-4/3)^2-(1/6*2*4)

DELTA = 4/9

DELTA > 0

t = ((4/9)^(1/2)+4/3)/(1/6*2) or t = (4/3-(4/9)^(1/2))/(1/6*2)

t = 6 or t = 2

t in { 2, 6 }

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